Red Sox outfielder Mookie Betts is the runaway winner of the American League Most Valuable Player Award. Betts got 28 of the 30 first place votes.

One first place vote went to Mike Trout while the other went to J.D. Martinez.

Trout did finish second in the total votes. Jose Ramirez of Cleveland was third and Martinez was fourth.

Betts led all of major league baseball with a .346 batting average. He had 32 home runs, 80 RBI, 30 steals and 129 runs scored.

Betts had already won a 2018 Gold Glove, Silver Slugger Award and the Heart and Hustle Award from MLB Alumni Players Association.

He is the 12th Red Sox player to win American League MVP, joining names like Yaz, Williams, Foxx, Lynn and Rice. Dustin Pedroia was the last Sox player to win it in 2008.

FIRST PLACE VOTES: Betts 28. Trout 1, Ramirez 0, Martinez 1

SECOND PLACE VOTES: Betts 2, Trout 24, Ramirez 1, Martinez 2

THIRD PLACE VOTES: Betts 0, Trout 2, Ramirez 10, Martinez 8